Web4. If for an A.P., S41 = 4510, find t21. 5. If for an A.P., t10 = 57 and t15 = 87, find t21. 6. A sum of Rs. 3900 is paid off in 12 installments, such that each installment is Rs.10 more … WebIn the given sequence if the difference between two consecutive terms ( t n + 1 - t n) is constant then the sequence is called Arithmetic Progression (A.P.). In this sequence t n + …
In an ap it is given that T 8=31 and t 13=45 find the AP - BYJU
Web7. Find t21, if S41 = 4510 in an A.P. 8. In an A.P. t10=57 and t15=87 then find t21. 9. If Rs.3900 will have to repay In 12 monthly instalments such that each instalment being more than the preceding one by Rs.10, then find the amount of the first and last instalment. 10. WebJul 26, 2024 · Oligonucleotides have many important applications, including as primers in polymerase chain reactions and probes for DNA sequencing. They are proposed as a diagnostic and prognostic tool for various diseases and therapeutics in antisense therapy. Accordingly, it is necessary to develop liquid chromatography and solid phase extraction … how to see battery usage on windows 10
In an A.P 10th term is 57 & 15th term is 87 then find 11th …
WebLet the number of terms in the A.P. be n. Then, t n = 101 Since t n = a + (n – 1)d, 101 = 1 + (n – 1) (2) ∴ 101 = 1 + 2n – 2 ∴ 101 = 2n – 1 ∴ 102 = 2n ∴ n = 102 2 = 51 Now, S n = n t t n n 2 ( t 1 + t n) ∴ S 51 = 51 2 ( 1 + 101) = 51 2 ( 102) = 51 × 51 = 2601 ∴ The sum of odd natural numbers from 1 to 101 is 2601. WebIn an arithmetic sequence to = -49 and t15 = -84, find the value of t1. A Question 12 (2 points) If to = 23 and t11 = 38 in an arithmetic sequence, find an expression for tn . ... 35, 22+35= 57 5 , 4, 9, 13, 22, 35, 57, 92 / 149 [ 13 + 9 = 22] 35 + 57 = 92 92 +57 = 149, So any term is Sum of breeding two terms Hence last :4 terms are 35, 57, 92 ... WebWe know that the formula for the nth term is t n=a+(n−1)d, where a is the first term, d is the common difference. It is given that the nth term is t 15=55 and the first term is a=13, therefore, t n=a+(n−1)d ⇒55=13+(15−1)d ⇒55=13+14d ⇒14d=55−13 ⇒14d=42 ⇒d= 1442=3 Hence, d=3 Solve any question of Arithmetic Progression with:- Patterns of problems > how to see bcc in outlook received items